Patrick Mahomes Named "AFC Offensive Player of the Week" for Second Time This Season

Mahomes threw for 249 yards and three touchdowns in Sunday’s victory over Tampa Bay

The football-watching world witnessed another one of "those games" from quarterback Patrick Mahomes last Sunday, and for the second time this season, that brilliant performance has earned him some recognition from the league.

Mahomes was named the "AFC Offensive Player of the Week" on Wednesday after completing 23-of-37 passes for 249 yards and three touchdowns in the Chiefs' victory over Tampa Bay on Sunday night.  Mahomes engineered touchdown drives on four of the Chiefs' first five possessions, quickly amassing a double-digit advantage that Kansas City never relinquished.

It marked his 30th career game with three or more passing touchdowns in just 67 total starts, meaning that Mahomes has thrown for 3+ scores in 45 percent of his games. Those 30 performances with 3+ touchdowns are also the most in the NFL since 2018 by a wide margin.

Mahomes' brilliance on Sunday night went beyond just the box score, however, as he made numerous "Houdini" throws for which he has become synonymous. That included a completion on third down despite being tackled by a defender early in the game and an acrobatic touchdown pass a bit later that featured a 360-degree spin around Pro Bowl linebacker Devin White. Mahomes is a special player, and when he plays like he did on Sunday, the Chiefs are a very difficult squad to beat.

This is the ninth-career "Offensive Player of the Week" award for Mahomes, which are the most for any player in franchise history. It's already his second time earning the award this season, as he also did so following Week 1.

Mahomes will now look to keep things rolling next week as the Chiefs host the Las Vegas Raiders at GEHA Field at Arrowhead Stadium on Monday Night Football.